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prog


Challenge^2: Floating Point without Errors

28 2020-10-18 12:37

>>27
Its not required to represent the series as 1/10^n(its merely for convenience ):
1/10/10/10/10/... can be converted to a series of multiplications
1*(1/10)*(1/10)*(1/10)*...=0
Now we move the series to the right by dividing the 0 by
1=0/(1/10)/(1/10)/(1/10)/... division by 1/10 is equivalent to multiplying by 10/1, which result in
1=0*10*10*10*10... which was already already discussed here >>22
And shown to be equal exactly 0.

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